The lifetimes of a certain electronic component are known to be normally distributed with a mean of 1,400 hours and a standard deviation of 600 hours.
For a random sample of 25 components, find the probability that the sample mean is less than 1300 hours.
A |
0.2033 |
|
B |
0.8213 |
|
C |
0.1487 |
|
D |
0.5013 |
Solution :
Given that ,
mean = = 1400
standard deviation = = 600
= / n = 600 / 25 = 120
P( < 1300) = P(( - ) / < (1300 - 1400) / 120)
P(z < -0.83)
= 0.2033
Probability = 0.2033
option A is correct
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