A sample of size n = 68 is drawn from a population whose standard deviation is σ = 23.Find the margin of error for a 99% confidence interval for the mean μ.
Group of answer choices
2.789
5.467
0.8713
7.185
Solution :
Given that,
Population standard deviation =
= 23
Sample size = n =68
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576 ( Using z table )
Margin of error = E = Z/2* ( /n)
= 2.576 * (23 / 68)
= 7.185
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