Question

A sample of size n = 68 is drawn from a population whose standard deviation is...

A sample of size n = 68 is drawn from a population whose standard deviation is σ = 23.Find the margin of error for a 99% confidence interval for the mean μ.

Group of answer choices

2.789

5.467

0.8713

7.185

Homework Answers

Answer #1

Solution :

Given that,

Population standard deviation =    = 23
Sample size = n =68

At 99% confidence level the z is ,

  = 1 - 99% = 1 - 0.99 = 0.01

/ 2 = 0.01 / 2 = 0.005

Z/2 = Z0.005 = 2.576   ( Using z table )

Margin of error = E = Z/2* ( /n)

= 2.576 * (23 / 68)

= 7.185

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of size n = 50 is drawn from a population whose standard deviation is...
A sample of size n = 50 is drawn from a population whose standard deviation is o= 26.   Find the margin of error for a 90% confidence interval for u. If the sample size were n= 40, would the margin of error be larger or smaller
A sample of size n=71 is drawn from a population whose standard deviation is u=15. Part...
A sample of size n=71 is drawn from a population whose standard deviation is u=15. Part 1 of 2 (a) Find the margin of error for a 95% confidence interval for u. Round the answer to at least three decimal places. The margin of error for a 95% confidence interval for u is? Part 2 of 2 (b) If the confidence level were 90%, would the margin of error be larger or smaller? (Larger/smaller), because the confidence level is (lower/higher).
A simple random sample of size 11 is drawn from a normal population whose standard deviation...
A simple random sample of size 11 is drawn from a normal population whose standard deviation is σ=1.8. The sample mean is ¯x=26.8. a.) Construct a 85% confidence level for μ. (Round answers to two decimal place.) margin of error: lower limit: upper limit: b.) If the population were not normally distributed, what conditions would need to be met? (Select all that apply.) the population needs to be uniformly distributed σ is unknown simple random sample large enough sample size...
A sample of size =n62 is drawn from a normal population whose standard deviation is =σ8.8...
A sample of size =n62 is drawn from a normal population whose standard deviation is =σ8.8 The sample mean is=x44.69 (a) Construct a 95% confidence interval for μ Round the answer to at least two decimal places. A 95% confidence interval for the mean is <μ< . (b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid? Explain. The confidence interval constructed in part (a) (would or would not) be valid since...
1)A sample of size  is drawn from a population whose standard deviation is  Find the margin of error...
1)A sample of size  is drawn from a population whose standard deviation is  Find the margin of error for a  confidence interval for μ. 2)A researcher wants to construct a 98% confidence interval for the proportion of elementary school students in Seward County who receive free or reduced-price school lunches. What sample size is needed so that the confidence interval will have a margin of error of 0.09? 3)An Internet service provider sampled 540 customers and found that 55 of them experienced an...
A sample of size n=100 is drawn from a normal population whose standard deviation is o=9.4....
A sample of size n=100 is drawn from a normal population whose standard deviation is o=9.4. The sample mean is x=42.53. Part 1 of 2 (a) Construct a 80% confidence interval for u. Round the answer to at least two decimal places. An 80% confidence interval for the mean is __<u<__.    Part 2 of 2 (b) If the population were not approximately normal, would the confidence interval constructed in part (a) be valid Explain. The confidence interval constructed in...
A sample​ mean, sample​ size, population standard​ deviation, and confidence level are provided. Use this information...
A sample​ mean, sample​ size, population standard​ deviation, and confidence level are provided. Use this information to complete parts​ (a) through​ (c) below. x=54, n=14, σ=5, confidence level=99% A. Use the​ one-mean z-interval procedure to find a confidence interval for the mean of the population from which the sample was drawn. The confidence interval is from ___to___ B. Obtain the margin of error by taking half the length of the confidence interval. What is the length of the confidence​ interval?...
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x ̅, is found to be 108, and the sample standard deviation, s, is found to be 10. Construct a 99% confidence interval for μ if the sample size n is 30.
A simple random sample of size n is drawn from a population that is normally distributed....
A simple random sample of size n is drawn from a population that is normally distributed. The sample​ mean, x overbar​, is found to be 108​, and the sample standard​ deviation, s, is found to be 10. 1. A) Construct a 96​% confidence interval about μ if the sample​ size, n, is 24. 1. B) Construct a 96​% confidence interval about μ if the sample​ size, n, is 20. How does increasing the sample size affect the margin of​ error,...
A simple random sample of size n=23 is drawn from a population that is normally distributed....
A simple random sample of size n=23 is drawn from a population that is normally distributed. The sample mean is found to be x bar=68 and the sample standard deviation is found to be s=15. Construct a 90?% confidence interval about the population mean. The 90?% confidence interval is ?(nothing?,nothing?).
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT