A student bikes to school by traveling first dN = 1.00 miles north, then dW = 0.400 miles west, and finally dS = 0.200 miles south. Part A Part complete Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking. Let d? N be the displacement vector corresponding to the first leg of the student's trip. Express d? N in component form. Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.
(dN)x,(dN)y = 0,1.00
Part B: Similarly, let d? W be the displacement vector corresponding to the second leg of the student's trip. Express d? W in component form. Express your answer as two numbers separated by a comma. Be careful with your signs.
Part A)
(dN)x = 0, (dN)y = 1.00
so, = (0, 1.00)
Part B)
Now, (dW)x = -0.400, (dN)y = 0
so, = (-0.400, 0)
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