A converging lens and a concave mirror are placed a distance D = 133 cm apart. The lens is placed such that it is to the left of the refelcting side of the mirror. The lens has focal length f1 = 5 cm, and the mirror has focal length f2 = 6 cm. If an object is placed a distance of do = 35 cm to the left of the lens, what is the image distance in centimeters from the lens? Round your answer to two decimal places.
object distance for the first lens,
u1 = 35 cm
let v1 is the image distance.
use, 1/u1 + 1/v1 = 1/f1
1/v1 = 1/f1 - 1/u1
1/v1 = 1/5 - 1/35
v1 = 5.83 cm
This image acts as object for the mirror.
object distance for the mirror, u2 = 133 - 5.83
= 127.17 cm
f2 = 6 cm
let v2 is the object distance for the mirror.
use,1/u2 + 1/v2 = 1/f2
1/v2 = 1/f2 - 1/u2
1/v2 = 1/6 - 1/127.17
v2 = 6.30 cm
This image again acts as object for the lens.
so, object distance, u3 = 133 - 6.30 = 126.7 cm
let v3 is the image distance.
use,
1/u3 + 1/v3 = 1/f1
1/v3 = 1/f1 - 1/u3
1/v3 = 1/5 - 1/126.7
v3 = 5.21 cm <<<<<<<<<---------Answer
The final image is 5.21 cm from the lens in the left side.
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