Question

A 2.30-kg object is moving along the x-axis at 1.50 m/s. As it passes the origin, two forces F→1 and F→2 are applied, both in the y-direction (plus or minus). The forces are applied for 2.70 s, after which the object is at x = 4.05 mm, y = 11.4 mm. If F→1=13.0 j^N, what's F→2?

Answer #1

A 2.30-kg object is moving along the x-axis at 1.90 m/s. As it
passes the origin, two forces F⃗ 1 and F⃗ 2 are applied, both in
the y-direction (plus or minus). The forces are applied for 2.80 s,
after which the object is at x = 5.32 m, y = 11.8 m. . i tried
0i-5.077j that is not correct nor is just -5j express anwser in
Fx2,please.
If F⃗ 1=11.0j^NF→1=11.0j^N, what's F⃗ 2F→2?

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