Question

A
ball of mass 2.25 kg is released from rest at height 5.29 m above
the floor. It falls, hits the ground, and rebounds to height 3.19 m
above the floor. Assume none of the losses are due to air friction.
Find the impulse, in N-s, exerted by the floor on the ball. The
sign of your answer will give the direction of the impulse.

Answer #1

A
ball of mass 5.93 kg is released from rest at height 7.62 m above
the floor. It falls, hits the ground, and rebounds to height 3.2 m
above the floor. Assume none of the losses are due to air friction.
Find the work done against friction, in J, on the ball during the
contact with the ground

A rubber ball of mass 0.175 kg is released from rest from a
height of 1.25 m. It rebounds from the floor to reach a height of
0.630 m. What impulse was applied to the ball by the floor? (You
may safely ignore air resistance. Enter the magnitude in kg ·
m/s)

A ball falls from height of 20.0 m, hits the floor, and rebounds
vertically upward to height of 15.5 m. Assume that
mball = 0.335 kg.
(a) What is the impulse (in kg · m/s) delivered to the ball by
the floor?
b) If the ball is in contact with the floor for 0.0400 seconds,
what is the average force (in N) the floor exerts on the ball?

a
ball of mass 0.175kg is dropped from rest from a height of 1.25m.
it rebounds from the floor to reach a height of 0.825m. what
impulse was given to the ball by the floor? magnitude______
kg

After falling from rest from a height of 27 m, a 0.46 kg ball
rebounds upward, reaching a height of 17 m. If the contact between
ball and ground lasted 2.1 ms, what average force was exerted on
the ball?

A ball of mass m falls from rest from a height of y1, collides
with the ground and bounces back up to y2. The collision time with
the ground is ?t. A) Determine the momentum of the ball immediately
before the collision with the ground. B) Determine the momentum of
the ball immediately after the collision with the ground. C)
Determine the average force exerted on the ball during the
collision. Now let: m = 0.080 kg y1 = 3.0...

After falling from rest from a height of 33 m, a 0.60-kg ball
rebounds upward, reaching a height of 23 m. If the contact between
ball and ground lasted 2.3 ms, what average force was exerted on
the ball? (Enter the magnitude.)
N

a 50.0 grams ball is released from rest from initial height of
100 meters, the ball falls vertically downward to the ground and
rebound to a lower height of 81% which mean the ball rebound to 81
percent of previous height for the first bound. 81 meters. a)what
is the speed of the ball immediately after the first bounce? b)
what height does the ball reach after the fifth bounce? c) what is
the impulse from the ground on the...

A stone 0.44 kg mass is released from rest from a height of 29.4
m above the ground. Ignoring air resistance and letting the ground
be the zero potential energy level,
Determine the final kinetic energy of the stone using energy
conservation principle only, not as a free fall.
Determine the work done on the stone by gravity.

1.
a tennis ball is dropped from a height of 2 m and it rebounds 95
cm. use g=10 m/s^2, and the tennis ball weights .058 kg.
a) find the change of momentum when the ball is at a height of
1.5 m downward and at 0.5 m downward. which i got -3.14 kg m/s for
the 1.5 m, and -0.18 kg m/s, and then what is the impulse exerted
on the object during that change of momentum?
b) compute...

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