Question

derivation of S= E/T+ KlnT+constant and then Lim S= K ln n. The derivation (step by)...

derivation of S= E/T+ KlnT+constant and then Lim S= K ln n. The derivation (step by) of entropy using canonical ensemble.

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find the domain of r(t) = 4e^−t i + e^−t j + ln(t − 1)k. (Enter...
Find the domain of r(t) = 4e^−t i + e^−t j + ln(t − 1)k. (Enter your answer using interval notation.)
ln [A] - ln [A]0 = - k t 0.693 = k t1/2 Show the calculation...
ln [A] - ln [A]0 = - k t 0.693 = k t1/2 Show the calculation of the decay constant (k) and the half-life (t1/2) of a radioactive nucleus if 44.3% of the material has decayed in 365 days.
Given r(t)=sin(t)i+cos(t)j−ln(cos(t))k, find the unit normal vector N(t) evaluated at t=0,N(0).
Given r(t)=sin(t)i+cos(t)j−ln(cos(t))k, find the unit normal vector N(t) evaluated at t=0,N(0).
Let {N(t), t ≥ 0} be a P P(λ). Compute P £ N(t) = k|N(t +...
Let {N(t), t ≥ 0} be a P P(λ). Compute P £ N(t) = k|N(t + s) = k + m ¤ for t ≥ 0, s ≥ 0, k ≥ 0, m ≥ 0
For a reaction under study, a graph of ln k versus 1/T (K−1) was prepared. The...
For a reaction under study, a graph of ln k versus 1/T (K−1) was prepared. The line of best fit to the data was determined to be: y = -8.09 × 103 x + 31.5 . What is the activation energy, E a, for this reaction in kJ/mol?
ONLY EXERCISE B! Find the mass that remains after t years. Step 1 Let y(t) be...
ONLY EXERCISE B! Find the mass that remains after t years. Step 1 Let y(t) be the mass (in mg) remaining after t years. Then we know the following. y(t) = y(0)ekt = 10    10 · ekt Step 2 Since the half-life is 30 years, then y(30) = 5   5 mg. Step 3 Thus, 5 = 10e30k, or e30k = 1/2   1/2 . Therefore, k =   $$−ln(2)30​     . Step 4 Now, remembering that ln(xn) = n ln(x) and that eln(z)...
A program takes time T(n) = k2n  where k is some constant and n is the input...
A program takes time T(n) = k2n  where k is some constant and n is the input size. The program is run twice on the same computer (so k is the same in both cases). The first run is with n = 4 and the time taken is 20 ms. The second run is with n = 10. What is the time taken for the second run, in milliseconds? (Type in just the number; don't type "ms" at the end.)
An Arrhenius plot (ln k vs. 1/T) for a second order reaction (2A -> C) produced...
An Arrhenius plot (ln k vs. 1/T) for a second order reaction (2A -> C) produced a straight line with a slope of -8.23e+03 K. What is the value of the Arrhenius pre-exponential if k = 4500 M-1 s-1 at 690 K?
How do I plot an appropriately labelled graph of ln (T∞ - Tt)against time (t) and...
How do I plot an appropriately labelled graph of ln (T∞ - Tt)against time (t) and calculate the rate constant (k) from the slope (gradient) using a line of best fit? I want the graph drawn by hand. The ln(A)0 are ( 2.31,2.16,2.09,2.37,2.34,2.06,2.09,2.09,2.09) and the time (10,20.5,30,40.1,50.27,60,70,80,90) 10 20.5 30 40.1 50.27 60 70 80 90 2.31 2.16 2.09 2.37 2.34 2.06 2.09 2.09 2.09
KNO3(s)= K+(aq) +NO3-(aq) Ksp=[K+(aq)][NO3-(aq)] Equation of line= -0.0003x+0.0039 Volume total(L) T (°C) [KNO3] (M) Ksp ln...
KNO3(s)= K+(aq) +NO3-(aq) Ksp=[K+(aq)][NO3-(aq)] Equation of line= -0.0003x+0.0039 Volume total(L) T (°C) [KNO3] (M) Ksp ln Ksp 1/T (1/K) 0.0250 67.20 6.57 43.138624 3.764419 0.002938 0.0292 56.00 5.62 31.621364 3.453833 0.003038 0.0334 46.70 4.92 24.168705 3.185059 0.003126 0.0376 39.90 4.37 19.070875 2.948162 0.003194 0.0418 36.80 3.93 15.430988 2.736378 0.003226 0.0461 33.30 3.56 12.686577 2.540544 0.003263 0.0510 29.80 3.22 10.365875 2.338519 0.003301 a. The equation can be represented in the following form: ln Ksp = -deltaH/R ( 1/T ) + deltaS/R...