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Johan throws a baseball with a horizontal component of velocity of 25 m/s. It takes 3.00s...

Johan throws a baseball with a horizontal component of velocity of 25 m/s. It takes 3.00s to come back to its original height. Calculate its horizontal range (x), its initial vertical component of velocity (vy) and its initial angle of projection.

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Answer #1

answer :

Range = 74.99 meter

Vertical velocity = 14.7m/s

Angle = 30.45 degree

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