A glider of mass 0.155 kg is moving to the right on a frictionless, horizontal air track with a speed of 0.760 m/s . It has a headon collision with a glider 0.294 kg that is moving to the left with a speed of 2.29 m/s . Suppose the collision is elastic. Find the magnitude of the final velocity of the 0.155 kg glider. Find the magnitude of the final velocity of the 0.294 kg glider.
m1 = 0.155 Kg
v1 = 0.760 m/s
m2 = 0.294 Kg
v2 = 2.29 m/s
Let the Final Velocities of glider be v1f and v2f .
Initial Momentum = m1*v1  m2*v2
Final Momentum = m1*v1f + m2*v2f.
Momentum Conservation 
Initial Momentum = Final Momentum
m1*v1  m2*v2 = m1*v1f + m2*v2f
0.155 * 0.760  0.294 * 2.29 = 0.155*v1f +
0.294*v2f
0.555 = 0.155*v1f + 0.294*v2f 1
As the Collision is Elastic, Kinetic Energy will be conserved

0.5 * m1v1^2 + 0.5 * m2v2^2 = 0.5 * m1v1f^2 + 0.5 * m2v2f^2
0.155 * 0.760^2 + 0.294 * 2.29^2 = 0.155*v1f^2 +
0.294*v2f^2
1.63 = 0.155*v1f^2 + 0.294*v2f^2 2
Solvinf for vf1 & vf2 using Eq 1 & 2 
vf1 = 3.23 m/s
vf2 = 0.18 m/s
ve sign means They are moving in the Left Direction.
Magnitude of the final velocity of the 0.155 kg glider =
3.23 m/s
Magnitude of the final velocity of the 0.294 kg glider = 0.18
m/s
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