Question

A radiation produces a number of ionizations equal to 8202465 in the gas of a gaseous detector. If it operates at the limit of Raether, what is the collected charge (in μC)?

Answer 1

The Raether limit is the physical limiting value of the multiplication factor (M) which is equal to 10⁸.

If number of ionizations is equal to N and the multiplication factor is equal to M then number of electrons collected at detector is equal to N*M.

For this case N = 8202465 and M = 10⁸ (Raether limit),

So the number of electrons collected at detector = N*M = 8202465*10⁸.

Charge of an electron, e = 1.602*10^-19 .

So the charge collected at detector, Q = N*M*e = (8202465*10⁸)*(1.602*10^-19) C

Q = 13140348.93*10^-11C = 131.4034893*10^-6C

Q = 131.4034893 μC (micro coulombs)

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