Question

Star E is known to be 19.9 light years away from the Earth. If you measure the flux from Star E to be 3.07*10^-3 (watts/(m^2)) what is the intrinsic luminosity of Star E? Your number should fill in the blank in the following statement of the luminosity in scientific notation and include 3 digits. L= ____*10^33

please show me every little step to get to the answer thank you so much for explaining

Answer 1

Answer:-

First write down the given data to understnad the input to the fomurla for intrinsic luminosity.

B = 3.07x10^-3 watts/m²

Distance d = 19.9 light years

let consider the formula for intrinsic luminosity

L = 4d²B

we have given flux in w/m2 so first we have to convert distance in meters

d= 19.9 light years.

1 light years = 9.461x10⁺¹² Km

19.9 light years = 1.882x10⁺¹⁴ Km

1 Km = 1000 Meters

d = 1.882x10⁺¹⁷ Meters.

now put the values in formula

L = 4*3.14* (  1.882x10⁺¹⁷ )²*3.07x10^-3

L= 1.3657x10³³ Watts.

Hence the luminosity of star E is L= 1.3657x10³³ Watts.