Question

The mean distance of a planet from the Sun is 1.54 times that of Earth from...

The mean distance of a planet from the Sun is 1.54 times that of Earth from the Sun. From Kepler’s law of periods, calculate the number of years required for the planet to make one revolution around the Sun;

**Do not use exponential numbers**

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose you discover a planet around a Sun-like star. From observations you find an orbital period...
Suppose you discover a planet around a Sun-like star. From observations you find an orbital period of one Earth month. Find the semi-major axis using one of Kepler’s laws.
The planet Earth orbits around the Sun and also spins around its own axis. A)  Calculate the...
The planet Earth orbits around the Sun and also spins around its own axis. A)  Calculate the angular momentum of the Earth in its orbit around the Sun in kg • m2/s B) Calculate the angular momentum of the Earth spining on its axis in kg•m2/s C) How many times larger is the angular momentum of the Earth in its orbit than the angular momentum of the Earth around its axis?
An undiscovered planet, many light-years from Earth, has one moon which has a nearly circular periodic...
An undiscovered planet, many light-years from Earth, has one moon which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.07500 × 105 km and the planet has a radius of 3775 km and a mass of 6.40 × 1022 kg, how long (in days) does it take the moon to make one revolution around the planet. The gravitational constant is 6.67 × 10-11 N·m2/kg2.
An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic...
An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.225×105 km and the planet has a radius of 3.150×103 km and a mass of 7.90×1022 kg , how long (in days) does it take the moon to make one revolution around the planet? The gravitational constant is 6.67×10−11N·m2/kg2.
Kepler’s Laws of Planetary Motion: 1. A newly discovered exoplanetary system has a planet orbiting its...
Kepler’s Laws of Planetary Motion: 1. A newly discovered exoplanetary system has a planet orbiting its host star at 50 times the distance from the Earth to the sun. If the orbital period of the planet is 40 Earth years, what is the mass of the host star? 2. The mass of the Earth is approximately 6 × 1026 kg. If the moon takes 27 days to orbit the Earth, how far is the moon from the Earth? 3. A...
An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic...
An undiscovered planet, many light-years from Earth, has one moon, which has a nearly circular periodic orbit. If the distance from the center of the moon to the surface of the planet is 2.090×10^5 km and the planet has a radius of 3.600×10^3 km and a mass of 7.00×10^22 kg , how long (in days) does it take the moon to make one revolution around the planet? The gravitational constant is 6.67×10^−11N·m^2/kg^2. T=___________days
Kepler, around 1600, upon his meticulous observations and measurements, had established a remarkable relationship between the...
Kepler, around 1600, upon his meticulous observations and measurements, had established a remarkable relationship between the revolution period T of a planet around the Sun, and the distance R of it to the Sun, as T2-R3. Show, how Newton about a century later, could, not only derive this relationship, as (with the familiar notation), T2=[(4π2/GM]R3, but also, could fix Kepler’s “proportionality constant”, thusly becoming 4π2/GM. The quantity G, is the gravitation constant, and M is the mass of the Sun....
A star with a radius four times that of our Sun is observed to have a...
A star with a radius four times that of our Sun is observed to have a rough blackbody spectrum that peaks around 400nm. The star illuminates a planet with the mass of the Earth at a distance of 0.7AU. This planet has a radius twice that of the Earth and absorbs a power of 2.82*1019 W. a) What is the planet’s albedo? The constant in Wien’s law is 2.9*10-3 m x K b) Assuming the equilibrium temperature is approximately that...
At what distance from the Sun is the intensity of sunlight three times the value at...
At what distance from the Sun is the intensity of sunlight three times the value at the Earth? (The average Earth-Sun separation is 1.496 x 1011 m.)
Suppose there were a planet in our Solar System orbiting at a distance of 0.5 AU...
Suppose there were a planet in our Solar System orbiting at a distance of 0.5 AU from the Sun, and having ten times the mass and four times the radius of Earth. For reference, the Earth has a mass of 5.97 × 1024 kg and a radius of 6,378 km. a) Calculate the density of this hypothetical planet. b) Based on your answer from part a), what do you think this planet would be made of? Explain your reasoning. c)...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT