Question

Consider an Ising chain of N spins with interaction constant J and free boundary conditions. (a)...

Consider an Ising chain of N spins with interaction constant J and free boundary conditions.

(a) If all the spins are parallel, what is the energy of the system?

(b) What is the energy change if an inner spin is flipped?

(c) Is there a relationship between domain size and the energy of the chain? Explain briefly.

Science   Advanced-Physics   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Consider a system of three non-interacting spins in equilibrium with a magnetic field H (this system...
Consider a system of three non-interacting spins in equilibrium with a magnetic field H (this system is not really macroscopic, but is illustrative). Each spin can have only two possible orientations: parallel to H, with magnetic moment u and energy (-u H), or antiparallel with magnetic moment -u and energy (uH). a) List and identify all possible states of the system. b) If it is known that the system has an energy (-uH): i. What are the accessible states? ii....
1. Under constant-volume conditions, 4200 J of heat is added to 1.4 moles of an ideal...
1. Under constant-volume conditions, 4200 J of heat is added to 1.4 moles of an ideal gas. As a result, the temperature of the gas increases by 103 K. How much heat would be required to cause the same temperature change under constant-pressure conditions? Do not assume anything about whether the gas is monatomic, diatomic, etc. 2. A system gains 3080 J of heat at a constant pressure of 1.36 × 105 Pa, and its internal energy increases by 4160...
± Free Energy and Chemical Equilibrium The equilibrium constant of a system, K, can be related...
± Free Energy and Chemical Equilibrium The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG, using the following equation: ΔG∘=−RTlnK where T is standard temperature in kelvins and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the...
The equilibrium constant of a system, K, can be related to the standard free energy change,...
The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG∘, using the following equation: ΔG∘=−RTlnK where T is a specified temperature in kelvins (usually 298 K) and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the equilibrium values....
The equilibrium constant of a system, K, can be related to the standard free energy change,...
The equilibrium constant of a system, K, can be related to the standard free energy change, ΔG∘, using the following equation: ΔG∘=−RTlnK where T is a specified temperature in kelvins (usually 298 K) and R is equal to 8.314 J/(K⋅mol). Under conditions other than standard state, the following equation applies: ΔG=ΔG∘+RTlnQ In this equation, Q is the reaction quotient and is defined the same manner as K except that the concentrations or pressures used are not necessarily the equilibrium values....
A chain of metal links with total mass m = 6 kg is coiled up in...
A chain of metal links with total mass m = 6 kg is coiled up in a tight ball on a low-friction table. You pull on a link at one end of the chain with a constant force F = 69 N. Eventually the chain straightens out to its full length L = 1.1 m, and you keep pulling until you have pulled your end of the chain a total distance d = 3.9 m (diagram is not to scale)....
Trial Spring Constant (N/m) Displacement (m) Potential Energy (J) 1 200 .1 1 2 200 .2...
Trial Spring Constant (N/m) Displacement (m) Potential Energy (J) 1 200 .1 1 2 200 .2 4 3 200 .3 9 4 200 .4 16 5 200 .5 25 25 1. In Excel, plot a graph of Potential Energy vs. Displacement and a graph of Potential Energy vs. (Displacement)2 to determine what relationship exists between the Potential Energy and displacement (linear or quadratic). Include the two graphs in the space below.
1. Consider the system of 46g (1 mole) sample of liquid ethanol at 1bar of pressure...
1. Consider the system of 46g (1 mole) sample of liquid ethanol at 1bar of pressure in aan open beaker on a cold hot plate in a lab that is 20C . Given the data below explain the conditions that must occur for the sample to convert from the liquid to the gas. C2H5OH (lq) C2H5OH (vap) The enthalpy (∆H) for this conversion is a measure of how much energy it takes to break the bonds between the ethanol molecules...
1) The free energy change for the following reaction at 25 °C, when [Pb2+] = 1.18...
1) The free energy change for the following reaction at 25 °C, when [Pb2+] = 1.18 M and [Cd2+] = 7.90×10-3 M, is -65.9 kJ: Pb2+(1.18 M) + Cd(s)> Pb(s) + Cd2+(7.90×10-3 M) ΔG = -65.9 kJ What is the cell potential for the reaction as written under these conditions? Answer: ___V Would this reaction be spontaneous in the forward or the reverse direction? 2) Use the standard reduction potentials located in the 'Tables' linked above to calculate the standard...
2 Equipartition The laws of statistical mechanics lead to a surprising, simple, and useful result —...
2 Equipartition The laws of statistical mechanics lead to a surprising, simple, and useful result — the Equipartition Theorem. In thermal equilibrium, the average energy of every degree of freedom is the same: hEi = 1 /2 kBT. A degree of freedom is a way in which the system can move or store energy. (In this expression and what follows, h· · ·i means the average of the quantity in brackets.) One consequence of this is the physicists’ form of...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT