Question

19. De Broglie's conjecture was to assert that

a. light, if it has wavelength λ, also has momentum p = h / λ.

b. a particle, if it has momentum p, also has wavelength λ = h / p.

c. mass and energy are equivalent.

20. The source of all electromagnetic waves is :

Answer #1

**Note: The Q 20 does not have options so, I just answered
it generally.**

**Solution:**

19.)

Ans: **B a particle, if it has momentum p, also has
wavelength
= h / p.**

Reason:

The de Broglie relation asserts that a particle moving with momentum p can behave as if it were a wave of wavelength (wavelength = h/p).

This relation is the origin of wave-particle duality, which means that matter can show either particle like or wavelike behavior depending on the conditions of the observation.

20.)

Ans: **Accelerating electric charges.**

Reason: Vibrating electric charge changing electric and magnetic waves.

I hope you understood the problem and got your answers, If yes rate me!! or else comment for a better solutions.

Louis de Broglie's bold hypothesis assumes that it is possible
to assign a wavelength λ to every particle possessing some momentum
p by the relationship λ = h p , where h is Planck's constant ( h =
6.626 × 10 − 34 J ⋅ s ). This applies not only to subatomic
particles like electrons, but every particle and object that has a
momentum. To help you develop some number sense for de Broglie
wavelengths of common, everyday objects,...

Just as light waves have particle behavior, a moving particle
has a wave nature. The faster the particle is moving, the higher
its kinetic energy and the shorter its wavelength. The wavelength,
λ, of a particle of mass m, and moving at
velocity v, is given by the de Broglie relation
λ=hmv
where h=6.626×10−34 J⋅s is Planck's constant.
This formula applies to all objects, regardless of size, but the
de Broglie wavelength of macro objects is miniscule compared to
their...

The de Broglie wavelength of a quantum-mechanical particle with
momentum p is given by Y=h/p, where h is plancks constant. Use this
to show that Fermi energy for a free Fermi gas is, with a numerical
factor, equal to the kinetic energy of a particle whose de Broglie
wavelength is equal to the average interparticle spacing in the
gas.

An ultraviolet photon has energy of 6.63x10-19 J.
Find the wavelength of the UV light. Use E=hc/λ with h= 6.63 x
10-34 J sec and c=3x108 m/s. What are some
appliances/equipment that use the uv light?

A photon has a wavelength that is the same as the de Broglie
wavelength of an electron.
(a) How does the momentum of the photon, compare to the momentum of
the electron,
(b)How does the energy of the photon, compare to the total
energy of the electron

1. we learn that _____
a.
red light has a smaller wavelength and lower frequency than blue
light.
b.
red light has a longer wavelength and higher frequency than blue
light.
c.
red light has a longer wavelength but the same frequency as blue
light.
d.
red light has a longer wavelength and lower frequency than blue
light.
2. we learn that ____
a.
velocities of electromagnetic waves range from 10-16
m to 104 m/s.
b.
wavelengths of electromagnetic waves...

A photon has a frequency of 7.50 x 1014 Hz,
a) Determine the energy and the momentum of this photon.
b) If all the energy of this photon were to be converted to
mass, determine the equivalent mass for the particle.
c) A microscopic specimen has a wavelength of
d) Determine the energy and the momentum of this photon.
e) If all the energy of this photon were to be converted to
mass, determine the equivalent mass for the particle....

Find the wavelength (in nm) of a photon whose energy is 6.70 ×
10-19 J.
The maximum wavelength that an electromagnetic wave can have and
still eject electrons from a metal surface is 507 nm. What is the
work function W0 of this metal? Express your
answer in electron volts.
In the Compton effect, an X-ray photon of wavelength 0.16 nm is
incident on a stationary electron. Upon collision with the
electron, the scattered X-ray photon continues to travel in...

Calculate the linear momentum, and the de Broglie wavelength
of:
a) a 0.75 kg bullet that is fired at a speed of 100 m /
s,
b) a non-relativistic electron with a kinetic energy of 2.0
eV, and
c) a relativistic electron with a kinetic energy of 208
keV.
!!!! # !! Remember that for relativistic particles: ? = ? ? +
? "? and ? = ?? = ? + ?" ?, the mass
of the electron is 9.11...

1) *Particles & waves in free space*
a) Consider a particle with mass m travelling through free
space with velocity v.
What is momentum of the particle?
What is the kinetic energy of the particle?
b) In quantum mechanics, any particle can be represented as a
wave. What are the wavelength and
frequency associated with the particle in part a?
c) Now consider a beam of light propagating in a vacuum. The
wavelength of the light is 500nm.
What is...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 6 minutes ago

asked 8 minutes ago

asked 9 minutes ago

asked 17 minutes ago

asked 55 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago