Question

Two
small charged objects attract each other with a force F when
separated by a distance d/2. If the charge on each object is
reduced to one-fourth of its original value and the distance
between them is reduced to d/4 the force in the second case is
related the force in the first case by :

" I want a solution with explanation "

Answer #1

Let q_{1} and q_{2} be the two charges. When
they are separated by a distance r, the force between them is

In the first case r=d/2, the force is

In the second case, the distance is r=d/4, the charges are
q_{1}'=q_{1}/4 and q_{2}'=q_{2}/4,
the force is

Using (1)

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