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Two charges attract each other with a force of 2.8 N. What will be the force...

Two charges attract each other with a force of 2.8 N. What will be the force if the distance between them is reduced to one-ninth of its original value?

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Answer #1

Coulomb's constant = k

Charge on the first particle = q1

Charge on the second particle = q2

Initial distance between the particles = d1

Force between the two particles = F1 = 2.8 N

New distance between the two particles = d2

The distance between the particles is reduced to one-ninth it;s original value.

d2 = d1/9

New force between the two particles = F2

F2 = 81F1

F2 = 81(2.8)

F2 = 226.8 N

Force between the charges if the distance between them is reduced to one-ninth its original value = 226.8 N

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