Given that n1 = 1.5, if the angle of incidence equals 30 degrees and the angle of refraction equals 45 degrees, find the value of n2.
What is the speed of light in m/s in medium n1?
Refractive index of medium 1 = n1 = 1.5
Refractive index of medium 2 = n2
Angle of incidence = 1 = 30o
Angle of refraction = 2 = 45o
By Snell's Law,
n2 = 1.06
Speed of light in vacuum = c = 3 x 108 m/s
Speed of light in medium 1 = v1
v1 = 2 x 108 m/s
a) Refractive index of the second medium = 1.06
b) Speed of light in medium 1 = 2 x 108 m/s
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