By what factor does the resistance of a copper wire change if its length quadruples and its diameter quadruples? (If the resistance doubles, enter "2"; if it decreases by a factor of three, enter "1/3", etc.)
Resistivity of copper =
Initial length of the copper wire = L1
Initial diameter of the copper wire = D1
Initial cross-sectional area of the copper wire = A = D12/4
Initial resistance of the copper wire = R1
New length of the copper wire = L2 = 4L1
New diameter of the copper wire = D2 = 4D2
New cross-sectional area of the copper wire = A2 = D22/4
The resistance of the copper wire changes by a factor of 1/4.
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