Question

An object is placed 3 cm from a concave lens of focal length 4 cm. (a) Draw a ray diagram for the situation. (b) Calculate the size and position of the image. (c) If the image is real or virtual and explain from part b above how you know this.

Answer #1

An object is placed 4 cm away from a concave lens of focal
length 3 cm. A convex lens of focal length 5 cm is placed 4 cm away
from the concave lens in the same direction (so the distance
between convex lens and the object is 8 cm). Use any method to
figure out if the final image is real/virtual, upright/inverted and
find its distance from the convex lens.
Explain in thorough detail.
draw a proper ray diagram for...

A concave lens has a focal length of magnitude 10 cm. It is
placed a distance of 25 cm from a concave mirror with a focal
length of magnitude 15 cm. An object is set a distance of 22 cm in
front of the lens. The observer is at the same location as the
object, so the light from the object goes through the lens,
reflects off the mirror, and comes back through the lens to the
observer.
Draw the...

A convex lens with a focal length of magnitude 4.0 cm and a
concave lens with a focal length of magnitude 10 cm are separated
by a distance of 18 cm as shown in the diagram below. The convex
lens is on the left, and the concave lens is on the right. An
object is then placed 6.0 cm to the left of the convex lens.
Locate the final image. State the distance of the final image
to the right...

1. A converging lens has a focal length of 14 cm. An object is
18 cm to the left of the lens.
Find the image position
The magnification
Real or virtual?
Erect of inverted?
e. Draw the ray diagram using principal rays and a ruler.
f. If the object was located 7 cm to the left of the lens, draw
the ray diagram.

A) An object is placed 26 cm in front of a converging lens of
focal length 5 cm. Another converging lens of focal length 10 cm is
placed 20 cm behind the first lens.
1) Find the position of the final image with respect to the second
lens. ____cm
2) Find the magnification of the final image. _____
B) A diverging lens of focal length −12cm projects the image of
an object onto a wall. What is the object distance if...

. Diverging lens 1 (focal length f1 = −20.0 cm) is placed a
distance of d = 45.0 cm to the left of diverging lens 2 (focal
length f2 = −15.0 cm). An object is placed p1 = 25.0 cm to the left
of diverging lens 1 and has a height of h = 16.0 cm.
(a) Where is the image formed by diverging lens 1 (i.e. what
is q1)? What is this image’s height and is it upright or...

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

An object is placed 25 cm in front of a concave mirror with a
focal length of 15 cm.
Determine the position of the image formed by the
mirror.
Is the image real or virtual? How do you know?
Determine the magnification of the image.
Is the image upright or inverted? How do you know?
Does the image appear to be larger or smaller than the object?
How do you know?
please show all work for each question asked.

An object 10cm tall is placed 8cm in front of a lens with focal
distance f = -12cm. Draw a diagram at proper scale of this
situation. Calculate using the lens equations the size, and
position of the image. Is the image real or virtual?

An object 6 cm high is placed 12 cm in front of a 4 cm focal
length convex lens.
(a) Draw a ray diagram to produce an image.
(b) Calculate the image location and magnification using the
lens equation.
(c) How close is your image position and height to your
calculated value (% difference)?

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