Question

An object 10cm tall is placed 8cm in front of a lens with focal distance f = -12cm. Draw a diagram at proper scale of this situation. Calculate using the lens equations the size, and position of the image. Is the image real or virtual?

Answer #1

Position of image can be find using below formula

Where u = object distance

v= image distance

A) An object is placed 26 cm in front of a converging lens of
focal length 5 cm. Another converging lens of focal length 10 cm is
placed 20 cm behind the first lens.
1) Find the position of the final image with respect to the second
lens. ____cm
2) Find the magnification of the final image. _____
B) A diverging lens of focal length −12cm projects the image of
an object onto a wall. What is the object distance if...

An object is placed 3 cm from a concave lens of focal length 4
cm. (a) Draw a ray diagram for the situation. (b) Calculate the
size and position of the image. (c) If the image is real or virtual
and explain from part b above how you know this.

A diverging lens, f= 20, is placed 10cm to the left of a
converging lens, f=20 cm. The final image of an object placed to
the left of the diverging lens is real, and 70 cm away from the
diverging lens. Draw a complete ray diagram to scale showing four
rays leaving the object and arriving at the final image

An
object is placed 5cm in front of a diverging lens of focal length
25 cm. A second converging lens of focal length 15cm is positioned
20 cm to the right of the first lens. What is the final image
distance? What is the magnification of the final image? Is it
upright of inverted? Real or virtual?

An object is placed 78.1 cm in front of a diverging lens with a
focal length of magnitude 37.3 cm. A converging lens having a focal
length of magnitude 27.49 cm is placed 105.3 cm past the first
lens. Where is the final image formed. Is this image Real or
Virtual. Inverted or Non-Inverted? Also calculate the
magnification.

A converging lens of focal length f1 = +22.5 cm is placed at a
distance d = 60.0 cm to the left of a diverging lens of focal
length f2 = −30.0 cm. An object is placed on the common optical
axis of the two lenses with its base 45.0 cm to the left of the
converging lens. (The thin-lens approximation may be assumed to
hold.) (a) Calculate the location of the final image and its
overall magnification with respect...

An object 4.0 cm tall is placed in front of a converging lens
whose focal length 22 cm. Where is the image formed, and what are
its characteristics, if the object distance is
(a) 15 cm
(b) 36 cm?

A 3.0-cm-tall object is placed 45.0 cm from a diverging lens
having a focal length of magnitude 20.0 cm.
a) What is the distance between the image and the lens?
b) Is the image real or virtual?
c) What is the height of the image?

A 3.00-cm tall object is placed 18.0 cm from the center of a
converging lens with a 24.0 cm center of curvature.
a. Determine a scale, then use graph paper and color pencils or
pens to neatly draw a complete
ray diagram to scale.
b. Based on the scale of your ray diagram determine the
image distance, height, and magnification.
c. Based on your drawing state whether the image is
real or virtual, upright, or inverted.
d. Use the mirror...

An object is placed in front of a converging lens (convex lens)
with a radius of curvature of 4.88 cm and focal length of 2.44 cm.
An image is formed the object. (a) Calculate how far is the lens
from the object if the image is real. (b) How far is image from the
lens? (c) is the image upright or inverted, and is the image
magnified or diminished? (d) Draw the ray diagram to confirm your
result prediction.

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