For modeling and calculation purposes, architects treat air as an incompressible fluid. As an architect's intern, you are doing the specs on a dorm air conditioning system that is designed to replace the air in each room every thirty minutes. If the rooms each have a volume of 205 m3 and they are supplied by ducts with a square cross section, determine the following.
(a) the length of each side of a duct if the air speed in the
duct is to be 4.0 m/s
m
(b) the length of each side of a duct if the air speed at the duct
is to be a value twice this speed.
m
Part A.
We know that Volume flow rate is given by:
Q = V*A
V = Speed of sir through duct = 4.0 m/sec
Given that duct have square cross-section, So Suppose length of duct is L, then
A = Cross-section area = L^2
Q = flow rate of air = 205 m^3 per 30 min = 205 m^3/(30*60 sec) = 0.1139 m^3/sec
So,
Q = V*A = V*L^2
L = sqrt (Q/V) = sqrt (0.1139/4.0)
L = 0.169 m = length of each side of duct
Part B.
Now when air speed is doubled, than
V = 2*4.0 m/sec = 8.0 m/sec
So, Now
L = sqrt (Q/V) = sqrt (0.1139/8.0)
L = 0.119 m = length of each side of duct
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