why is the cross product of 2 parallel vectors always 0? How can it be determined that a × b = |a| |b| sin(θ) n from the other formula
Cross product means the area of the parallelogram formed by two vector as the adjacent sides now if these are parallel then area = 0 thus cross product is zero
Now a*b = absin(angle)
For a and b being parallel , angle = 0
Thus a*b = 0
Now a*b = absin(angle) let angle be A let a be a vector along x axis , b be vector at an angle A to it now the n will be in z direction
So the cross will be in z direction
We are given the z component as
Cz = axby-aybx
Here ax = a , bx = bcosA , ay=0 and by= bsinA
Thus Cz = absinA -0
Hence this formula can be obtained like above
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