An impala is an African antelope capable of a remarkable vertical leap. In one recorded leap, a 45 kg impala went into a deep crouch, pushed straight up for 0.21 s, and reached a height of 2.5 m above the ground.
Part A
To achieve this vertical leap, with what force did the impala push down on the ground?
PartB
What is the ratio of this force to the antelope's weight?
Impulse vector = F?????t = ?mv? = m?v?
[the deer pushes the ground with an average force F??? for time =
?t s and then gains a vertical velocity v from rest as the ground
exerts the same force on the deer upwards as per Newton's III law
]
the deer's velocity in time ?t changes from 0 to v
F???(0.21) = ?mv? = m?v = 45[v - 0] = 45v -------------------->
(i)
also from Energy Conservation => the kinetic energy of the deer
is changed to potential energy at the highest point of the
leap.
=> k.e =
Get Answers For Free
Most questions answered within 1 hours.