A rocket is fired at an angle from the top of a tower of height h0 = 61.2 m . Because of the design of the engines, its position coordinates are of the form x(t)=A+Bt2 and y(t)=C+Dt3, where A, B, C , and D are constants. Furthermore, the acceleration of the rocket 1.20 s after firing is a=( 5.10 i+ 4.80 j)m/s2. Take the origin of coordinates to be at the base of the tower.
a) Find the constant A.
b) Find the constant B.
c) Find the constant C.
d) Find the constant D.
e) At the instant after the rocket is fired, what is its acceleration vector? Enter your answers numerically separated by a comma.
f) At the instant after the rocket is fired, what is its velocity? Enter your answers numerically separated by a comma.
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