Question

How many grams of solid are present at equilibrium for a mixture that contains 47 grams...

How many grams of solid are present at equilibrium for a mixture that contains 47 grams of Cu and 53 grams of Ni at 1300 °C?

W_alpha = (C_L - C_0) / (C_alpha - C_L)

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Answer #1

where is the weight of the solid present

from the graph we can have as = 47gms

         from the graph

      

       

      

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