Consider the following linear program: MIN Z = 60A + 50B
s.t. 10A + 20B ≤ 200
8A + 5B ≤ 80
A≥2
B≥5
Solve this linear program graphically and determine the optimal quantities of A, B, and the value of Z using iso-profit method.
Given,
subject to,
The contraints are shown graphically below:
The feasible region is the area bound by the points shown on the graph.
Now the isoprofit line represented by is drawn on the graph and shown below:
We see that the isoprofit line passes through point (2,5). This gives the minimum value of Z
Hence, A= 2, B=5 and minimum value of Z is
Min Z = 60 x 2 + 50 x 5 = 120 + 250 = 370
Get Answers For Free
Most questions answered within 1 hours.