Question

A state of stress is given by: σx = −200 MPa σy = 150 MPa σxy=...

A state of stress is given by: σx = −200 MPa
σy = 150 MPa
σxy= −70 MPa

Determine the principal stresses and the maximum shear stress, as well as their orientation, using
the Mohr circle construction.
b. Explain why the engineering stress in a tension test increases from yield to ultimate and then
decreases from ultimate to fracture.

Homework Answers

Answer #1

(B) The stress in tension test Increases from yield to ultimate tension to completely break the bonds of the intermittent particles and deform it plastically. Once the bonds are broken fully then the stress reduces and ultimately fracture occures.

Please dear thumpsup for the answer. Thank you.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A machine element is subjected to the following bi-axial state of stress: σx=80 MPa σy=20 MPa;...
A machine element is subjected to the following bi-axial state of stress: σx=80 MPa σy=20 MPa; τxy=40 MPa. If the shear strength of the material is 100 MPa, and the yield strength is 300 MPa, determine the factor of safety using (a)Tresca’s Maximum-Shear-Stress Theory and (b) von Mises’ Distortion Energy Theory.
The state of plane stress on an element is shown below. Let σx=30.0 MPaσx=30.0 MPa, σy=−100.0...
The state of plane stress on an element is shown below. Let σx=30.0 MPaσx=30.0 MPa, σy=−100.0 MPaσy=−100.0 MPa, and τxy=50.0 MPaτxy=50.0 MPa. Part A - Construction of Mohr’s circle for the state of stress
For the following data, using Mohr’s circle of stress and trigonometry, a) Find the principal stresses...
For the following data, using Mohr’s circle of stress and trigonometry, a) Find the principal stresses and show their sense on properly orianted isolated elements, b) Find the maximum (principal) shear stresses with the associated normal stresses and show the results on properly oriented elements. σx = -40 MPa, σy = -30 MPa, and τ = +25 MPa.
At a point in a bracket, the stress on two mutually perpendicular planes are 100 N/mm2...
At a point in a bracket, the stress on two mutually perpendicular planes are 100 N/mm2 (tensile) and 50 N/mm2 (tensile). The shear stress across the planes is 80 N/mm2. Find using Mohr stress circle or otherwise calculate: Magnitude and direction of the resultant stress on plane making an angle of 200 with the plane of the first stress. Maximum shear stress and location of its plane. c. Principal stresses and the location of principal planes