Question

The base of a solid is the region bounded by y = 9 and y = x 2 .

The cross-sections of the solid perpendicular to the x axis are rectangles of height 10. The volume of the solid is

Answer #1

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The region bounded by y=x^3, y=x, x=0 is the base of a solid. a)
If the cross sections are perpendicular to the
x-axis are right isosceles
triangles (congruent leg lies on the base), find
the volume of the solid. b) If the cross sections are perpendicular
to the y-axis are equilateral
triangles, find the volume of the solid.

The base o a solid is the region in the xy plane bounded by y =
4x, y = 2x+8 and x = 0. Find the the volume of the solid if the
cross sections that are perpendicular to the x-axis are: (a)
Squares; (b) semicircles.

The base of a solid is the region in the first quadrant bounded
by the graph of y=cos x, and the x- and y-axes. For the solid, each
cross-section perpendicular to the x-axis is an equilateral
triangle. What is the volume of the solid?
A- 0.785
B-0.433
C -1.000
D- 0.340

Consider the solid S described below. The base of S is the
region enclosed by the parabola y = 1 - 9x^2 and the x-axis.
Cross-sections perpendicular to the x-axis are isosceles triangles
with height equal to the base. Find the volume V of this solid.

Find the volume of the solid whose base is rotating around the
region in the first quadrant bounded by y = x^5 and y = 1.
A) and the y-axis around the x-axis?
B) and the y-axis around the y-axis?
C) and y-axis whose cross sections are perpendicular to x-axis
are squares

3) The base of a solid is the first quadrant region between the
curve y = 2 ⋅ sin xand the x-axis on the interval [ 0 , π ].
Cross sections perpendicular to the x-axis are semi circles with
diameters in the x-y plane. Sketch the solid. Find the volume of
the solid.

1. A volume is described as follows:
1. the base is the region bounded by y=2− 1/32 x^2 and y=0
2. every cross section parallel to the x-axis is a
triangle whose height and base are equal.
Find the volume of this object.
volume =
2. Find the volume of the solid obtained by rotating the region
bounded by
y=5x^2, x=1, and y=0, about the x-axis.
Need help with both please, thank you!

Find the volume of the of the solid described as follows: The
base of the solid is the region enclosed by the line y=4-x, the
line y=x, and the y-axis. The cross sections of the region that are
perpendicular to the x-axis are isosceles triangles whose height is
equal to half their base. What is the volume of this solid (rounded
to two decimal places)? Please show work. Thanks much!

Find the volume of the solid ? if the base of ? is the
triangular region with
vertices (0,0), (3,0), and (0,2) and cross sections perpendicular
to y-axis are semicircles.
Please explain how you found x/3 + y/2 =1

1) A volume is described as follows:
1. the base is the region bounded by y=2−2/25x^2 and y=0
2. every cross-section parallel to the x-axis is a
triangle whose height and base are equal.
Find the volume of this object.
volume =
2) The region bounded by f(x)=−4x^2+24x+108, x=0, and y=0 is
rotated about the y-axis. Find the volume of the solid of
revolution.
Find the exact value; write answer without decimals.

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