Find the absolute extrema of the function on the closed interval
f(x)= 1 - | t -1|, [-7, 4]
minimum =
maximim =
f(x)= x^3 - (3/2)x^2, [-3, 2]
minimim =
maximim =
f(x)= 7-x, [-5, 5]
minimim =
maximim =
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