Question

Find the equation of the tangent to the curve ? = 5^−?^2 at the point on...

Find the equation of the tangent to the curve ? = 5^−?^2 at the point on the curve where ? = 1. Express the equation in the simplest form. Show ALL work!

Math   Calculus   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Find an equation for the line tangent to the following curve at the point (4,1). 1−y=sin(x+y^(2)−5)...
Find an equation for the line tangent to the following curve at the point (4,1). 1−y=sin(x+y^(2)−5) Use symbolic notation and fractions where needed. Express the equation of the tangent line in terms of y and x. equation:
Q1. (a) Find the equation of the tangent to the curve f(x)=x^2+4x+2 at the point where...
Q1. (a) Find the equation of the tangent to the curve f(x)=x^2+4x+2 at the point where the gradient is 8. (b) Find the equation of the normal at this point, where normal gradient times tangent gradient is -1.
Find the (a) slope and (b) equation of the tangent to the curve at the point...
Find the (a) slope and (b) equation of the tangent to the curve at the point corresponding to ? = 4? + 2???(?), ? = −1 + 3???(?) for ? = ?.
1)   If 67+3?(?)+4?^2(?(?))^3=0 and ?(−4)=−1, find ?′(−4).      f'(-4)= 2)   Find an equation of the tangent...
1)   If 67+3?(?)+4?^2(?(?))^3=0 and ?(−4)=−1, find ?′(−4).      f'(-4)= 2)   Find an equation of the tangent line to the curve ?^2=?^3(5−?) (a piriform) at the point (1,2). The equation of this tangent line can be written in the form ?=??+?, where ?=_________ and ?=________ find m and b
Find the slope of the line tangent to the curve y=x^2 at the point (-0.9,0.81) and...
Find the slope of the line tangent to the curve y=x^2 at the point (-0.9,0.81) and then find the corresponding equation of the tangent line. Find the slope of the line tangent to the curve y=x^2 at the point (6/7, 36,49) and then find the corresponding equation to the tangent line.   answer must be simplified fraction
Find an equation of the tangent line to the curve at the given point. y =...
Find an equation of the tangent line to the curve at the given point. y = sec(x),    (π/3, 2)
Find an equation for the line tangent to the curve at the point defined by the...
Find an equation for the line tangent to the curve at the point defined by the given value of t.​ Also, find the value of d2y/dx2 at this point. x= sec2t-1 , y= cos(t) , t= pi/4
a) Find the equation of the tangent line to the curve x= 2sin2t, y= 3sint at...
a) Find the equation of the tangent line to the curve x= 2sin2t, y= 3sint at the point where the same. b) Find the points on the curve x= t^2-t+2, y=t^3-3t where the tangent is horizontal.
Find an equation of the tangent line to the curve ? ∙ ?^? + ? ∙...
Find an equation of the tangent line to the curve ? ∙ ?^? + ? ∙ ?^? = 1 at the point (0,1)
Find an equation of the tangent to the curve at the given point by both eliminating...
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the parameter. x = 4 + ln(t), y = t2 + 4, (4, 5)
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT