Question

Q) Find f.

f''(x)= −2+36x−12x^2, f(0)=7, f'(0)=12

f(x)=

Q) Find f

f''(t)=sint+cost, f(0)=2, f'(0)=3

f(t)=

Q) Find f

f''(x)=20x^3+12x^2+4, f(0)=4, f(1)=2

f(x)=

Answer #1

Find f(x).
1. f''(x) = (1/3) x^3 −3x^2 + 6x
2. f''(x) = −1 + 6x−12x^2, f(0) = 4, f'(0) = 12
3. f'''(x) = sinx, f(0) = 1, f'(0) = 2, f''(0) = 3

1. Find f. f ''(x) = 4 + 6x + 36x^2, f(0) = 2, f (1) = 13
f(x) =
2. What constant acceleration is required to increase the speed
of a car from 26 mi/h to 56 mi/h in 3 seconds? (Round your answer
to two decimal places.)
ft/s2

Find f.
f ''(x) = −2 + 36x −
12x2, f(0) =
8, f '(0) = 14

1.Find ff if
f′′(x)=2+cos(x),f(0)=−7,f(π/2)=7.f″(x)=2+cos(x),f(0)=−7,f(π/2)=7.
f(x)=
2.Find f if
f′(x)=2cos(x)+sec2(x),−π/2<x<π/2,f′(x)=2cos(x)+sec2(x),−π/2<x<π/2,
and f(π/3)=2.f(π/3)=2.
f(x)=
3.
Find ff if f′′(t)=2et+3sin(t),f(0)=−8,f(π)=−9.
f(t)=
4.
Find the most general antiderivative of
f(x)=6ex+9sec2(x),f(x)=6ex+9sec2(x), where −π2<x<π2.
f(x)=
5.
Find the antiderivative FF of f(x)=4−3(1+x2)−1f(x)=4−3(1+x2)−1
that satisfies F(1)=8.
f(x)=
6.
Find ff if f′(x)=4/sqrt(1−x2) and f(1/2)=−9.

1)Find F
f”(x)=-2+36x-12xsquer, f(0)=9, f’(0)=18
f(x)=?
2)Find a function f such that f’(x)=3x cube, and the line
81x+y=0 is tangent to the graph of f
f(x)=?

1) Find f.
f ''(t) =
9sqrt t, f(4) = 29, f'(4)= 10
2) Find f
f'''(x) = cos x, f(0) =4, f'(0) = 8, f''(0) = 9
3) Find f.
f ''(x) = −2 + 24x −
12x2, f(0) =
7, f '(0) = 12

Find the intervals on which f(x) = x^4 + 2x^3 − 36x^2 + 9x − 47
is concave down and up, along with the x-coordinates of any
inflection points. Justify all your work.

Show that
-e^(-t)(sint) +3/2cos^2tsinte^(-t)
-e^(t)cost+3/2e^(-t)cos^2(t)sint
is equal to
-e^(-t)sint +e^(-t)cost

Find f.
f ''(x) = −2 + 18x −
12x2, f(0) =
7, f '(0) = 12

Let f(x)=2x^3 - 9x^2 +12x -4
Find the intervals of which f is increasing or decreasing
Find the local maximum and minimum values of f
Find the intervals of concavity and the inflection points

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