A company manufactures two types of electric hedge trimmers, one of which is cordless. The cord-type trimmer requires 2 hours to make, and the cordless model requires 6 hours. The company has only 600 work hours to use in manufacturing each day, and the packaging department can package only 200 trimmers per day. If the company profits are $40.50 for the cord-type model and $121.50 for the cordless model, how many of each type should the company produce per day to maximize profits?
Let the number of cord type trimmers be x
Let the number of cordless model be y
Maximize Profit = 40.50x + 121.50y
Constraints:
2x + 6y <= 600 [Total working hours must be less than or equal to 600]
x + y <=200 [Maximum number of packing can be done for 200 models]
Solving this equation, we get the optimal solution as x=0 and y=100
Number of models made of type cord trimmers = 0
Number of cordless trimmers will be 100
Maximize Profit = $12150
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