The system of linear equations has a unique solution. Find the solution using Gaussian elimination or Gauss Jordan elimination. Show all your work.
x + y + z = 11
2x ? 3y + 2z = 7
4x + y ? 3z = 7
Augmented matrix for given system of equations
solution using Gaussian elimination or Gauss Jordan elimination
Your matrixt
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 1 | 1 | 11 |
2 | 2 | -3 | 2 | 7 |
3 | 4 | 1 | -3 | 7 |
Find the pivot in the 1st column in the 1st row
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 1 | 1 | 11 |
2 | 2 | -3 | 2 | 7 |
3 | 4 | 1 | -3 | 7 |
Eliminate the 1st column
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 1 | 1 | 11 |
2 | 0 | -5 | 0 | -15 |
3 | 0 | -3 | -7 | -37 |
Make the pivot in the 2nd column by dividing the 2nd row by -5
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 1 | 1 | 11 |
2 | 0 | 1 | 0 | 3 |
3 | 0 | -3 | -7 | -37 |
Eliminate the 2nd column
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 0 | 1 | 8 |
2 | 0 | 1 | 0 | 3 |
3 | 0 | 0 | -7 | -28 |
Make the pivot in the 3rd column by dividing the 3rd row by -7
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 0 | 1 | 8 |
2 | 0 | 1 | 0 | 3 |
3 | 0 | 0 | 1 | 4 |
Eliminate the 3rd column
X1 | X2 | X3 | b | |
---|---|---|---|---|
1 | 1 | 0 | 0 | 4 |
2 | 0 | 1 | 0 | 3 |
3 | 0 | 0 | 1 | 4 |
Solution set:
x = 4
y = 3
z = 4
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