Monopoly: Work It Out
Earlier we mentioned the special case of a monopoly where MC = 0. Let’s find the firm’s best choice when more goods can be produced at no extra cost. Since so much e-commerce is close to this model—where the fixed cost of inventing the product and satisfying government regulators is the only cost that matters—the MC = 0 case will be more important in the future than it was in the past. For each demand curve, calculate the profit-maximizing level of output and price as well as the monopolist's profit.
a. ?=200−?, fixed cost = 1,000.
Profit-maximizing output Q = ________
Profit-maximizing price P = $__________
Monopolist's profit: $__________
b. ?=4,000−?, fixed cost = 900,000 (Driving the point home from part a)
Profit maximizing output Q = _________
Profit-maximizing price P = $__________
Monopolist's profit: $___________
c. ?=120−12?, fixed cost = 1,000
Profit-maximizing quantity Q = __________
Profit-maximizing price P = $__________
Monopolist's profit: $__________
A monopolist maximizes profit by equating Marginal revenue (MR) with MC.
Profit = Q x (P - MC) - Fixed cost
(a)
P = 200 - Q
Total revenue (TR) = P x Q = 200Q - Q2
MR = dTR/dQ = 200 - 2Q
200 - 2Q = 0
2Q = 200
Q = 100
P = 200 - 100 = 100
Profit = 100 x (100 - 0) - 1,000 = 100 x 100 - 1,000 = 10,000 - 1,000 = 9,000
(b)
P = 4,000 - Q
TR = 4,000Q - Q2
MR = 4,000 - 2Q
4,000 - 2Q = 0
2Q = 4,000
Q = 2,000
P = 4,000 - 2,000 = 2,000
Profit = 2,000 x (2,000 - 0) - 900,000 = 2,000 x 2,000 - 900,000 = 4,000,000 - 900,000 = 3,100,000
(c)
P = 120 - 12Q
TR = 120Q - 12Q2
MR = 120 - 24Q
120 - 24Q = 0
24Q = 120
Q = 5
P = 120 - (12 x 5) = 120 - 60 = 60
Profit = 5 x (60 - 0) - 1,000 = 5 x 60 - 1,000 = 300 - 1,000 = -700 (loss)
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