Question

THIS IS IN PYTHON 3.0

Let's call the first function power(a,b). Use the built-in power function a**b to write a second function called testing(c) that tests if the first function is working or not.

I already have the function power(a,b), which is as follows:

def power(a, b):

    if (b == 0): return 1

    elif (int(b % 2) == 0):

        return (power(a, int(b / 2)) *

               power(a, int(b / 2)))

    else:

        return (a * power(a, int(a / 2)) *

                   power(a, int(b / 2)))

Answer 1

*** I Kindly request you to Please provide a positive rating******

Source code:

def power(a, b): # power function

if (b == 0):
return 1

elif (int(b % 2) == 0):

return (power(a, int(b / 2)) *

power(a, int(b / 2)))

else:

return (a * power(a, int(a / 2)) *

power(a, int(b / 2)))

def testing(c): # testing funtion of power
if(c== pow(a,b)):
return "power function is successfully tested ";
else:
return "power function does not work and not successfull!";
  
a = int(input("Enter an integer1 >>>"))
b = int(input("Enter an integer2 >>>"))
c= power(a,b)
print("result of power(a,b) =",c)
print("result of testing: \n ",testing(c));

Output:

Enter an integer1>>>4

Enter an integer2>>>2

power function is successfully tested