Question

code that will take a binary file and searching for a byte pattern and then print to a new text file. code written in python. printing the data from the binary to human legible text. prints data when pattern in found.

Answer 1

The code for the above problem:

#Function for pattern search =============================
def search(pat, txt):

    flag = 0
    M = len(pat)
    N = len(txt)
    for i in range(N - M + 1):
        j = 0

        while(j < M):
            if (txt[i + j] != pat[j]):
                break
            j += 1

        if (j == M):
            print("Pattern found at index ", i)
            flag = 1

    return flag


#Create binary file ===================================
with open('Bin_file.bin', 'wb') as f:
    bin_input = input("Enter the string : ")
    bin_input = ' '.join(format(x, 'b') for x in bytearray(bin_input, 'utf-8'))
    bin_input = bytes(bin_input, 'utf-8')
    A = f.write(bin_input)


#Open binary file ======================================
with open('Bin_file.bin', 'rb') as f:
    s = f.read()


#convert byte formate to string
txt = s.decode('utf-8')
print(txt)

#Take input of the searched pattern
pat = input("Enter the pattern you want to search : ")
Sear = search(pat, txt)

binary_values = pat.split()

ascii_string = ""

#Convert from binary to character
for binary_value in binary_values:
    an_integer = int(binary_value, 2)
    ascii_character = chr(an_integer)
    ascii_string += ascii_character

#Create new text file and write to convert the pattern to human language 
if(Sear == 1):
    with open('new_text.txt', 'w') as f:
        h_lang = ascii_string
        B = f.write(h_lang)

with open('new_text.txt', 'r') as f:
    B = f.read()
    print(B)

Output: