Question

14.14 Structure - read and print structure

Assuming you have the following structure

struct Student {
    int id;
    string name;
    float GPA;
};

You are required to read students' information from an input file whose filename is provided by standard input; Please use std::cout to output students' name who have a GPA > 3.0 in the reversed order.

input

id=1234567 name=Peter GPA=3.6
id=1234568 name=Adina GPA=3.8
id=1234569 name=Mike GPA=3.0
id=1234569 name=Gina GPA=2.9

Note: input file may be empty.

output

Adina
Peter

step 1, count the numbers

step 2, create a dynamic array

step 3, read information into the created dynamic array

step 4, writer students' names in the reversed order to the screen

Answer 1

Code :

Instruction:

Count of data is done using getline.

Then dynamic array created and data stored in that array.

Then data retrieved for GPA > 3.0 and for reverse order that is accessed from last index.

Input the file name with extension as shown in output image.

---------------------------------------------------------------------------------------------------------------------------------------------------

#include <bits/stdc++.h>

using namespace std;

struct Student {
int id;
string name;
float GPA;
};

int main()
{
string inpfile,temp;
cout<<"Enter the file name with extension:"<<endl;
cin>>inpfile;
ifstream fileData;
fileData.open(inpfile);
if(!fileData)
{
cout<<"Error in file opening."<<endl;
return -1;
}
  
int noOfData = 0;
while(getline(fileData, temp))
{
noOfData++;
}
Student* studentData = new Student[noOfData];
  
for(int i=0;i<noOfData;i++)
{
fileData>>studentData[i].id>>studentData[i].name>>studentData[i].GPA;
}
  
for(int i = (noOfData-1); i >=0; i--)
{
if(studentData[i].GPA > 3.0)
{
cout<<studentData[i].name<<endl;
}
}
  
delete [] studentData;

fileData.close();

return 0;
}

Code image 1

Code image 2

Code image 3

Data image

Output image