Question

debug code on C(not C+ or C++)

I try to fix by myself, node part show error.
This program should work for scan 5 ints from the user
Using those 5 ints, it require construct a linked list of 5 elements.
After this, it sould prntf of the list using the PrintList.

#include <stdio.h>

struct Node{
   int data;
   Node* next;
};

int main(void){
   struct Node first = {0, 0};
   struct Node* second = {0, 0};
   Node third = {0, 0};
   struct Node fourth = {0, 0};
   struct Node fifth = {0, &first};

   int i;

   scanf(" %d", &i);
   first.data = i;

   scanf(" %d", &i);
   second.data = i
   first.next = &second;

   scanf(" %d", &i);
   third.data = i;
   second.next = third;

   scanf(" %d", &i);
   data = i;
   third.next = &fourth;

   scanf(" %d", &i);
   fifth.data = i;
   fourth->next = &fifth;

   PrintList(first);
}

PrintList(struct Node* n){
   while(n != 0){
       printf("%d ", n.data);
       n = n.next;
   }

   printf("\n");
}

Answer 1

CODE

#include <stdio.h>

struct Node{

int data;

struct Node* next;

};

void PrintList(struct Node* n){

while(n != NULL){

printf("%d ", n->data);

n = n->next;

}

printf("\n");

}

int main(void){

struct Node first = {0, 0};

struct Node second = {0, 0};

struct Node third = {0, 0};

struct Node fourth = {0, 0};

struct Node fifth = {0, 0};

int i;

scanf(" %d", &i);

first.data = i;

scanf(" %d", &i);

second.data = i;

first.next = &second;

scanf(" %d", &i);

third.data = i;

second.next = &third;

scanf(" %d", &i);

fourth.data = i;

third.next = &fourth;

scanf(" %d", &i);

fifth.data = i;

fourth.next = &fifth;

PrintList(&first);

}