Question

Consider the following function, that is supposed to return true only if provided two arrays a and b that are the same.

function arrayEqual(a, b) {
  for (let i = 0; i < a.length && i < b.length; ++i) {
    if(a[i] !== b[i]) {
      return false;
    }
  }
  return true;
}

Give three pairs of arrays for which the function correctly returns false, true and then incorrectly return true .

False

Pair 1.) a = , b =

Pair 2.) a = , b =

Pair 3.) a = , b =

True

Pair 1.) a = , b =

Pair 2.) a = , b =

Pair 3.) a = , b =

Incorrectly True

Pair 1.) a = , b =

Pair 2.) a = , b =

Pair 3.) a = , b =

Answer 1

FALSE:

Pair 1)a=[1,5,3] b=[1,2,3]

Pair 2)a=[45,6,56] b=[4,5,6]

Pair 3)a=[2,1,2,3] b=[1,2,3]

it return false for the above pair of arrays as the array numbers are not equal

TRUE:

Pair 1)a=[1,2,3] b=[1,2,3]

pair 2)a=[4,5,6] b=[4,5,6]

pair 3)a=[0,0,0,0]= b=[0,0,0,0]

it returns true for the above pair of arrays as the array numbers and even size of the array is equal

Incorrectly true:

pair a=[1,2,3] b=[1,2,3,4,5]

pair a=[3,4,5,6,7] b=[3,4,5,6]

pair a=[1] b=[1,2,3,4]

it returns true for the above pair of arrays as the array elements are equal but it is incorrect as the size of the arrays are not equal