Question

Write a program in C that takes a file name as the argument on the command line, and, if the file is a symbolic link, prints out the contents of that link (i.e. the file name that the link points to). If it is not a symbolic link, the program should print an error

int main ( int argc , char * argv [] ) {

// Check if the user gave an argument , otherwise print " ERROR : no argument "

// Check if the file can be read , otherwise print " ERROR : can ’t read "

// Check if it ’s a link , otherwise print " ERROR : not a symlink "

// Otherwise , print the contents of the symlink

}

Answer 1

If you have any doubts, please give me comment...

#include <stdio.h>

#include <sys/types.h>

#include <sys/stat.h>

#include <unistd.h>

int main(int argc, char *argv[]){

if(argc==1){

printf("ERROR : no argument\n");

return -1;

}

FILE *fp = fopen(argv[1], "r");

if(fp==NULL){

printf("ERROR : can ’t read\n");

}

else{

struct stat buf;

lstat(argv[1], &buf);

if(!S_ISLNK(buf.st_mode))

printf("ERROR : not a symlink\n");

else{

printf("The contents of file is: \n");

char line[1000];

while(!feof(fp)){

fscanf(fp, "%s", line);

printf("\n%s", line);

}

printf("\n");

}

fclose(fp);

}

return 0;

}