Question

C++ programming

Write a program that reads a comma-separated file (CSV) with integer values and prints the number of integer values in the file. Your program's input will be a string with the name of the file. If the file does not exist, then the program must print: Error opening the file

For example, given the following CSV file input1.csv:

1,10,20,30,40

The output of your program must be:

5

You can safely assume that the input file will be a valid CSV file.

Below is my code but I think I miss something which makes the program does not run. can someone give me the correct code? Thank you

#include <iostream>
#include <fstream>

using namespace std;

int main()
{
int input1;
ifstream inFS;
conut = 0;

inFS.open("input1.csv");
while (!inFS.eof()){
inFS >> input1;
if (!inFS.fail()){
cout << count(input1) << endl;
}
}

inFS.close();

return 0;
}

Answer 1

#include <iostream>
#include <fstream>
#include <string>
#include <cstdlib>
using namespace std;

int main() {
    ifstream inFS;
    int num, count = 0;
    string filename, s;
    cout << "Enter file name: ";
    cin >> filename;
    inFS.open(filename.c_str());
    if (inFS.is_open()) {
        while (getline(inFS, s, ',')) {
            num = atoi(s.c_str());
            cout << num << endl;
            ++count;
        }
        cout << "Number of values in file is " << count << endl;
        inFS.close();
    } else {
        cout << filename << " does not exists!" << endl;
    }
    return 0;
}