Question

Assume that x is at memory location 0x61fe18, and xptr is at memory location 0x61fe10.

What is printed by the below snippet of code?

int x;
int * xptr;
xptr = & x;
x = 12;

cout << x << endl;
cout << xptr << endl;
cout << &x << endl;
cout << &xptr << endl;
cout << *xptr << endl;

Answer 1

cout << x << endl; this will print 12 the value of x

cout << xptr << endl; this will print 0x61fe18 the memory address of x

cout << &x << endl; this will also print 0x61fe18 the memory address of x

cout << &xptr << endl; this will print 0x61fe10 the memory address of xptr

cout << *xptr << endl; this will print 12 the value stored at memory address 0x61fe18  ( of x)

So the output will look like

12

0x61fe18

0x61fe18

0x61fe10

12

Thanks.