Question

Modify the show() function written in Exercise 1 to alter the address in rates. Always use the expression *rates rather than *(rates + i) to retrieve the correct element. This is the function "Write a program that has a declaration in main() to store the following numbers in an array named rates: 6.5, 7.2, 7.5, 8.3, 8.6, 9.4, 9.6, 9.8, and 10.0. Include a function call to show() that accepts rates in a parameter named rates and then displays the numbers by using the pointer notation *(rates + i)." written in Excerise 1

Answer 1

We need to use *(rates + i) notation to show the content of the array.

Here is the desired output

And here is the C code as requested

#include <stdio.h>

void show(float *rates)
{
    for(int i=0;i<9;i++)
    {
        printf("%.1f\n",*(rates + i)); //.1 will round off float to 1 decimal place//
    }
}

int main()
{
    float rates[9] = {6.5, 7.2, 7.5, 8.3, 8.6, 9.4, 9.6, 9.8, 10.0};
    show(rates);

    return 0;
}

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