Question

write a C program to find whether the given number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is since 3**3 + 7**3 + 1**3 = 371.
Output:
Enter a number, or -999 to quit : 432
4**3 + 3**3 + 2**3 is not = 432
Enter a number, or -999 to quit : 371
3**3 + 7**3 + 1**3 is = 371

please use the for or do while loop only
Enter a number, or -999 to quit : -999

Answer 1

#include <stdio.h>

int main() {
    int n, num, d1, d2, d3;
    do {
        printf("Enter a number, or -999 to quit : ");
        scanf("%d", &n);
        if (n != -999) {
            num = n;
            d1 = n % 10;
            n /= 10;
            d2 = n % 10;
            n /= 10;
            d3 = n % 10;
            if (d1 * d1 * d1 + d2 * d2 * d2 + d3 * d3 * d3 == num) {
                printf("%d**3 + %d**3 + %d**3 is = %d\n", d3, d2, d1, num);
            } else {
                printf("%d**3 + %d**3 + %d**3 is not = %d\n", d3, d2, d1, num);
            }
        }
    } while (n != -999);
    return 0;
}