Question

The following data segment starts at memory address 2300h (hexadecimal) .data printString BYTE "Assembly is fun",0...

The following data segment starts at memory address 2300h (hexadecimal)

.data

printString BYTE "Assembly is fun",0

moreBytes BYTE 48 DUP(0)

dateIssued DWORD ?

dueDate DWORD ?

elapsedTime WORD ?

What is the hexadecimal address of dueDate?

2310h

2344h

2340h

2368h

Please explain the answer, I thought the answer was 2368h

Homework Answers

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Suppose a program contains the data segment definitions val DWORD ? results BYTE 11 DUP(?), 0...
Suppose a program contains the data segment definitions val DWORD ? results BYTE 11 DUP(?), 0 and the code segment contains dtoa results, val Now, assuming that val contains FFFFFFE3, what bytes will be placed in memory at results by the dtoa macro? (Your answer should be in hex and should be the proper size)
Consider the following data segment .data array1 WORD 10 DUP(?),0,0 array2 DWORD 4 DUP(3 DUP(?)) What...
Consider the following data segment .data array1 WORD 10 DUP(?),0,0 array2 DWORD 4 DUP(3 DUP(?)) What decimal value the instruction : mov EBX , SIZEOF array2 stores in EBX. Show your work for full credit.
I am designing a custom PC and have RAM with a capacity 64GB. Assuming each byte...
I am designing a custom PC and have RAM with a capacity 64GB. Assuming each byte of data is accessible with discrete Memory Address, what is the required Address Bus Width to access all data within the RAM? Explain your answer.
Consider a memory system with a 16 bit address and the following address decode logic. The...
Consider a memory system with a 16 bit address and the following address decode logic. The signals enrom, enram, and endev are the device enable signals for ROM, RAM, and I/O devices, respectively. ◦ csrom <= '1' when ax(15 downto 12 = "1101" or ax(15 downto 13 = "111" else '0'; ◦ csram <= '1' when ax(15 downto 13) = "001" or ax(15 downto 12) = "0100" else '0'; ◦ csdev <= '1' when ax(15 downto 8) = "00001" else...
(MIPS Assembly Language): Assume the following piece of MIPS code: label1: .text 0x4000fc lui $t0, 1022...
(MIPS Assembly Language): Assume the following piece of MIPS code: label1: .text 0x4000fc lui $t0, 1022 ori $t0, $t0, 2048 srl $t1, $t0, 18 sw $t0, 101($t1) slti $t2, $t1, 5 beq $t2, $0, label3 label2:... ... label3:... a) The code modifies a word in memory at the following address (circle one): (i) 1022 (ii) 101 (iii) 5 (iv) 10220000 (v) Other (provide your own answer): _________________ b) The following value is stored in memory (circle one): (i) 0x17 (ii)...
1. Assume there are three memory locations named h hand area, translate the following expression into...
1. Assume there are three memory locations named h hand area, translate the following expression into MIPS assembly language. No Floating point. Area= 1/2 b. h 2. Show the assembly statement that allocates a word in the data segment named area with an initial value of 10. 3. What are the contents of register $t0, $t1, and $t2? .data str:    .asciiz   "ab" .text main:   la $t0, str li    $t1, 0 loop: lb $t2, ($t0) beqz   $t2, eloop addi $t1,...
Assembly Programming in MIPS Write a program in MIPS assembler that performs the following computations: Prompts...
Assembly Programming in MIPS Write a program in MIPS assembler that performs the following computations: Prompts the user to enter two integers and stores the smaller one in the first data memory word (with the lowest address) and the larger one in the second data memory word. Then divides the larger word by the smaller one in integer and stores the integer quotient in the third data memory word and the remainder in the fourth data memory word. Finally, it...
1. The memory units that follow are specified by the number of words times the number...
1. The memory units that follow are specified by the number of words times the number of bits per word. How many address lines and input/output data lines are needed in each case? (a) 8K X 16 (b) 2G X 8 (c) 16M X 32 (d) 256K X 64 2. Give the number of bytes stored in each memory unit in question 1. 3. Word number 563 decimal in the memory shown in Fig. 7.3 (see Mano-Ch7.pdf) contains the binary...
Write an assembly program to compute the following expressions Create a list named ‘z’ of size...
Write an assembly program to compute the following expressions Create a list named ‘z’ of size 3 using DUP operator. Leave the list ‘z’ uninitialized. You can denote the items in the list as [z0, z1, z2]. z0 =x+13 z1 = y-x z2= r+z1-13 Where x, y, r are 16-bit integer memory variables. x = 7, y = 20, r = 4 Use the debugger to verify your answer. Please answer using this format for code: .386 .model flat, stdcall...
A) Is the code below secure? Explain your rationale. ExitProcess PROTO .data firstval qword 20002000h secondval...
A) Is the code below secure? Explain your rationale. ExitProcess PROTO .data firstval qword 20002000h secondval qword 11111111h thirdval qword 22222222h sum qword 0 .code main proc      mov rax,firstval                         add rax,secondval             add    rax,thirdval      mov    sum,rax      mov    ecx,0      invoke ExitProcess main endp end main b) Transmitted messages often include a parity bit, whose value is combined with a data byte to produce an even number of 1 bits. Suppose a message byte in the AL...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT