Question

A flow of 28 m^{3}/sec occurs in an earth-lined
trapezoidal channel having base width 3.0m, side slopes 1V:2H and
n= 0.022. Calculate the critical depth.

Answer #1

A discharge of 4.25 m3 /s occurs within a trapezoidal channel
with a base width of 3m, 3:1 side slopes (i.e. Z = 3), a
longitudinal bed slope of 0.0009 m/m with a Manning’s roughness
coefficient of 0.025 (i.e. sand). State the normal flow depth (yn)
critical flow depth (yc) and the Froude Number of the flowing
water.

3. A trapezoidal channel has a base width b = 8 ft and side
slopes 6H:1V. The frictional slope is Sf = 0.035 and the Manning
roughness coefficient is n = 0.014. Design a channel if channel
discharge is = 15.45 m3 /s using Mannings
equation. The farmer land is 3.482 acre with a
length of 951.43 ft. what is the best length for the grass
waterway?
Depth of channel, d=? (5).
Top width of the channel=? (3)
Freeboard of...

A trapezoidal concrete channel (n = 0.015) has side slopes of
2H:1V, a bottom width of 10.0 ft, and a longitudinal slope of
0.005.
(a) Compute the discharge rate (in cfs) and velocity (ft/s) when
the water depth is 3.0 ft.
(b) Compute normal depth and critical depth (in feet) for a
discharge rate of 300 cfs.

A trapezoidal channel has a bottom width of 5 m and side slopes
m = 2. If the flow rate is 20 m3/s, what is critical depth?

The discharge in a channel with bottom width 3 m is 12 m3 s–1.
If Manning’s n is 0.013 m-1/3 s and the streamwise slope is 1 in
200, find the normal depth if:
(a) the channel has vertical sides (i.e. rectangular
channel);
(b) the channel is trapezoidal with side slopes 2H:1V.
(Answer with steps plz)

In a trapezoidal channel with a constant width of b=3 m. and
side slopes of 1:3 (1 vertical, 3 horizontal) and discharge rate of
6 m3 /sec, if the maximum step upward height is z=0.5 m. not to
cause any choking, what is the water depth before and after this
maximum step upward. Draw the water surface profile and specific
energy curve (E vs y) for this flow.

A concrete, trapezoidal channel with a 5-m bottom width and side
slopes of 1:1 (H:V) discharges 35 m3/sec. The bottom slope of the
channel is 0.004. A dam is placed across the channel and raises the
water level to a depth of 3.4 m. determine the channel and flow
classification (e.g., M-2, S-1) upstream of the dam and explain
your supporting logic. then compute the water surface profile at
50-m intervals until you reach the hydraulic jump. Use a
spreadsheet...

Determine the normal depth, critical depth, and channel type
(mild, steep, etc.) for a trapezoidal channel with a base width of
22 and side slope 4 to 1. There is a flow rate of 1500 cfs flowing
through the channel. The overall longitudinal slope is 2% and the
channel is composed of soil (n=0.03).

7. A) Find the depth of water flowing through a triangular
channel having a bed slope of 1 in 3500 and side slope of 1:1, when
it carries 1.2 m3/s. Take Manning’s Coefficient N = 0.014
B) For a most economical trapezoidal section of side slope 2h: 5V,
bed slope of 1 in 2000 and C = 50. Find the rate of flow if the
bottom width of the channel is 5 m.

A hydraulic jump is formed in a trapezoidal channel of 2.0-m bed
width, 1:1 side slope, and carrying a discharge of 6.0 m3/s. The
initial and final depths of the jump are 0.5m and 2.0m,
respectively. Concrete blocks are placed to stabilize the jump. Cf
= 0.6. Construct the M-y diagram for the channel section. Find the
critical depth.

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