Question

For reactions 1 and 2, calculate the moles of NH4Cl produced or dissolved. Given: Volume HCl...

For reactions 1 and 2, calculate the moles of NH4Cl produced or dissolved.

Given:

Volume HCl (50.0mL), Mass HCl (51.5g), Volume NH3 (50.0mL), Mass of NH3 (51.5g), Molarity of HCl (0.9847), molarity of NH3aq (1.1mol/L).

In Reaction 1, calculate the moles of NH4Cl by using molarity (M) and volume (L) of the limiting reagent, HCl.

In Reaction 2, this can be found from the mass of the NH4Cl used and it's molar mass (53.49g/mol)

Please show step by step. Thank you. :)

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Answer #1

The total number of moles (n) of a solute is equal to the given mass of the solute divided by molar mass of the solute. The molarity (M) is defined as the total number of moles of solute per litre volume of the solution. The detailed solution is given below:

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