One mole of superheated water is evaporated at 383 K and 101 kPa. Calculate DS of the water and of the surroundings, DHv(373 K) = 47.3 kJ mol-1, Cp(H2O,l) = 75.4 J K-1 mol-1 , and Cp(H2O,g) = 30.36 + 9.61x10-3T + 11.8x10-7T2 (J K-1 mol-1). What is DS of the universe? The answer should be 126 , -122 , 4 J K-1 mol-1
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