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A chemist requires 0.392 mol Na2CO3 for a reaction. How many grams does this correspond to?

A chemist requires 0.392 mol Na2CO3 for a reaction. How many grams does this correspond to?

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Answer #1

moles of Na2CO3 = mass of Na2CO3 / molar mass of Na2CO3

mass of Na2CO3 = moles X molar mass

                              = 0.392 X 106

                              = 41.552 grams

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