The solubility limit of CaCl2*2H2O in boling water is 152g CaCl2*2H2O in 100g water. If you dissolved enough CaCl2*2H2O in water to reach this solubility limit, would the water boil if the water was initially 20.0 C? The answer is YES... I need the equation to prove it. How???
Moles of CaCl2.2H2O =
=1.03 mol
Mass of water = 100 g =0.1 kg
Molality = moles/kg = 1.03/0.1 = 10.3 m
Kb of water =0.512
Total number of ions CaCl2 can produce = i = 3 (Ca2+, and 2Cl- ions)
Formula to find elevation in boiling point
elevation in boiling point = 100 + 15.8 = 115.8 oC
So water boils and boiling temperature is = 115.8 oC
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